t^2=5.1

Solution for t^2=5.1 equation:

t^2=5.1

We move all terms to the left:

t^2-(5.1)=0

We add all the numbers together, and all the variables

t^2-5.1=0

a = 1; b = 0; c = -5.1;
Δ = b2-4ac
Δ = 02-4·1·(-5.1)
Δ = 20.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{20.4}}{2*1}=\frac{0-\sqrt{20.4}}{2}
=-\frac{\sqrt{}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{20.4}}{2*1}=\frac{0+\sqrt{20.4}}{2}
=\frac{\sqrt{}}{2}
$